solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
2
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
5.6
To find the [H+] concentration in a solution with a pOH of 0.253, you first need to find the pOH of the solution which is 14 - pOH = 14 - 0.253 = 13.747. Then, you can use the relation [H+][OH-] = 1.0 x 10^-14 to calculate the [H+] concentration. [H+] = 10^-13.747 = 1.93 x 10^-14 M.
The sum of pH and pOH is always equal to 14 in a neutral solution at 25°C. This is because pH is a measure of the concentration of H+ ions in a solution while pOH is a measure of the concentration of OH- ions. In a neutral solution, the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a sum of 14.
7.8
7.5
To find the pOH of a solution, first calculate the pH using the given [H⁺] concentration. In this case, [H⁺] = 2.5 x 10⁻⁵. Then use the equation pH + pOH = 14 to find the pOH. Thus, pOH = 14 - pH.
To find the pH, calculate -log[H+] using the concentration of hydrogen ions [H+]. To find the pOH, calculate -log[OH-] using the concentration of hydroxide ions [OH-]. The pH and pOH are related by the equation pH + pOH = 14 for a neutral solution.
To find the pOH of a solution when the H concentration is 1.7 x 10^-9 M, you can first calculate the pH using the formula: pH = -log[H+]. Then, you can find the pOH by subtracting the pH from 14, since pH + pOH = 14 in water. So, if the H concentration is 1.7 x 10^-9 M, the pH is 8.77, and the pOH is 14 - 8.77 = 5.23.
Since HNO3 is a strong acid, it completely dissociates in solution. HNO3 -> H+ + NO3-. Therefore, the concentration of H+ ions is the same as the concentration of the HNO3 solution, 0.0067M. pH = -log[H+] = -log(0.0067) ≈ 2.18. pOH = 14 - pH ≈ 11.82.
If an aqueous solution has a pOH value of 10.7 and is at standard temperature and pressure, the pH value is 14 - 10.7 = 3.3. From the definition of pH, this means that the logarithm (to base 10) of the molar concentration of H+, [H+] is -3.3. This can be written as +0.7 - 4. The antilog of 0.7 is 5, to the justified number of significant digits. Therefore, [H+] = 5 X 10-4.
Yes, for a neutral solution at room temperature, the pH and pOH values would be equal. Both would be around 7 due to the presence of equal concentrations of H+ and OH- ions in the solution.
The concentration of H+ ions in a solution determines its acidity; the higher the concentration of H+ ions, the lower the pH. The concentration of OH- ions in a solution determines its alkalinity; the higher the concentration of OH- ions, the higher the pH. pH is a logarithmic scale that represents the concentration of H+ ions in a solution.