1111 1111 1111 1111 = 2^16 = 65536
The largest decimal number that can be stored using 5 bits is 31. This is because 5 bits can represent binary numbers from 00000 (0 in decimal) to 11111 (31 in decimal). The maximum value is calculated as (2^5 - 1), which equals 31.
674
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
The largest binary number that can be obtained with 16 bits is 1111111111111111, which consists entirely of ones. In decimal, this binary number is equivalent to 65,535. This is calculated using the formula (2^{n} - 1), where (n) is the number of bits, so (2^{16} - 1 = 65,535).
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
674
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
31 - it's binary equivalent is 11111
The largest binary number that can be obtained with 16 bits is 1111111111111111, which consists entirely of ones. In decimal, this binary number is equivalent to 65,535. This is calculated using the formula (2^{n} - 1), where (n) is the number of bits, so (2^{16} - 1 = 65,535).
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.
In FoxPro, you can convert a decimal number to a binary number using the DECIMAL() and STR() functions. First, use DECIMAL() to get the binary representation, then format it as a string using STR(). Here's an example: binaryString = STR(DECIMAL(decimalNumber, 2)). This will give you the binary equivalent of the decimal number.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
write a c++ program to convert binary number to decimal number by using while statement
255 as a decimal number (also known as a base 10 number) = 11111111 in binary (also known as a base 2 number). In binary, each digit is known as a bit, and 8 bits are known as 1 byte. 255 is the largest (positive) number you can make in binary using only 8 bits (1 byte).