It means: O- oh M- my G- god W- what T- the F- f**k oh my god what the f**k
Oh, dude, a product of m and n is just the result of multiplying those two numbers together. It's like when you have m apples and n oranges, and you're too lazy to count them individually, so you just smash them together and get the total. So yeah, the product of m and n is just m times n. Easy peasy, lemon squeezy.
-log[1 X 10^-4 M OH(-)] = 4 14 - 4 = 10 pH ----------------
To write out a billion in Roman numerals, we would use the symbol "M" for 1000, repeated one thousand times, which represents one billion. Therefore, one billion in Roman numerals is written as "M" with a horizontal line above it, indicating multiplication by a thousand. This symbol is rarely used due to the complexity of writing out such large numbers in Roman numerals, as the system was not designed for such large values.
what is in M&M's
The concentration of OH- ions in a solution with a pOH of 4.22 is 5.24 x 10^-5 M.
omg means oh my god or oh m g
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
In 0.5 M NaOH, there is a 1:1 ratio of NaOH to OH- ions. Therefore, the concentration of OH- ions is also 0.5 M in the solution. To find the number of moles of OH- ions in one liter of 0.5 M NaOH, you simply multiple the concentration by the volume: 0.5 mol/L* 1 L = 0.5 moles of OH- ions.
To find the OH- concentration in water when you know the H3O+ concentration, you can use the formula Kw = [H3O+][OH-]. Given that Kw (at 25°C) is 1.0 x 10^-14, you can rearrange the equation to solve for OH-. In this case, [OH-] = Kw / [H3O+] which would equal 2.94 x 10^-12 M.
To find the pOH, take the negative logarithm of the hydroxide ion concentration. pOH = -log(OH-). Given [OH-] = 0.00015 M, pOH = -log(0.00015) ≈ 3.82.
The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.
M. W. Haznam has written: 'Oh, dokter'
it means OH MY GOD!! O= oh M= my GD= god :)
comb-oh or you could look at it as c-oh-m-oh
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
OH M G! See if he does!?