It means: O- oh M- my G- god W- what T- the F- f**k oh my god what the f**k
-log[1 X 10^-4 M OH(-)] = 4 14 - 4 = 10 pH ----------------
what is in M&M's
If you eat half, you eat an M.. Buh if you eat all, you eat an M and M
m y m
The concentration of OH- ions in a solution with a pOH of 4.22 is 5.24 x 10^-5 M.
omg means oh my god or oh m g
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
In 0.5 M NaOH, there is a 1:1 ratio of NaOH to OH- ions. Therefore, the concentration of OH- ions is also 0.5 M in the solution. To find the number of moles of OH- ions in one liter of 0.5 M NaOH, you simply multiple the concentration by the volume: 0.5 mol/L* 1 L = 0.5 moles of OH- ions.
To find the OH- concentration in water when you know the H3O+ concentration, you can use the formula Kw = [H3O+][OH-]. Given that Kw (at 25°C) is 1.0 x 10^-14, you can rearrange the equation to solve for OH-. In this case, [OH-] = Kw / [H3O+] which would equal 2.94 x 10^-12 M.
To find the pOH, take the negative logarithm of the hydroxide ion concentration. pOH = -log(OH-). Given [OH-] = 0.00015 M, pOH = -log(0.00015) ≈ 3.82.
The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.
comb-oh or you could look at it as c-oh-m-oh
it means OH MY GOD!! O= oh M= my GD= god :)
M. W. Haznam has written: 'Oh, dokter'
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
Never mind, I found it. S&M - Rihanna