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To determine the hydroxide ion concentration ([OH^-]) from a solution with a concentration of (2.0 \times 10^{-3} , M) of hydronium ions ([H_3O^+]), we can use the ion product of water at 25°C, which is (K_w = [H_3O^+][OH^-] = 1.0 \times 10^{-14}). Rearranging gives ([OH^-] = \frac{K_w}{[H_3O^+]}). Thus, ([OH^-] = \frac{1.0 \times 10^{-14}}{2.0 \times 10^{-3}} = 5.0 \times 10^{-12} , M).
What else can I help you with?
What does omgwtf mean?
It means: O- oh M- my G- god W- what T- the F- f**k oh my god what the f**k
Is 3 km greater than or less than 350 m?
Oh, dude, let me break it down for you. So, 3 km is actually equal to 3000 m, right? And 3000 m is definitely greater than 350 m. It's like comparing a pea to a watermelon, no contest.
What is a product of m and n?
Oh, dude, a product of m and n is just the result of multiplying those two numbers together. It's like when you have m apples and n oranges, and you're too lazy to count them individually, so you just smash them together and get the total. So yeah, the product of m and n is just m times n. Easy peasy, lemon squeezy.
What is the h3o plus in a solution with OH minus 2 x10 -8 m?
To find the concentration of ( \text{H}_3\text{O}^+ ) in a solution with ( \text{OH}^- = 2 \times 10^{-8} , \text{M} ), we can use the water dissociation constant ( K_w = 1 \times 10^{-14} ) at 25°C. The relationship is given by ( [\text{H}_3\text{O}^+] = \frac{K_w}{[\text{OH}^-]} ). Substituting in the values, we find ( [\text{H}_3\text{O}^+] = \frac{1 \times 10^{-14}}{2 \times 10^{-8}} = 5 \times 10^{-7} , \text{M} ).
What is the pH of a solution withOH equals 1 10-4?
-log[1 X 10^-4 M OH(-)] = 4 14 - 4 = 10 pH ----------------
What is the OH- in a solution with a pOH of 4.22?
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
What is omg generation?
omg means oh my god or oh m g
What is the OH in a solution with a pOH of 4.22?
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
How many moles of OH- ions are present in one liter of 0.5 M NaOH?
In 0.5 M NaOH, there is a 1:1 ratio of NaOH to OH- ions. Therefore, the concentration of OH- ions is also 0.5 M in the solution. To find the number of moles of OH- ions in one liter of 0.5 M NaOH, you simply multiple the concentration by the volume: 0.5 mol/L* 1 L = 0.5 moles of OH- ions.
What has the author M W Haznam written?
M. W. Haznam has written: 'Oh, dokter'
What is the pOH of a base if its OH is 0.00015 M?
To find the pOH, take the negative logarithm of the hydroxide ion concentration. pOH = -log(OH-). Given [OH-] = 0.00015 M, pOH = -log(0.00015) ≈ 3.82.
Given that you have a H3O concentration of 0.0034 M what is the OH-?
To find the OH- concentration in water when you know the H3O+ concentration, you can use the formula Kw = [H3O+][OH-]. Given that Kw (at 25°C) is 1.0 x 10^-14, you can rearrange the equation to solve for OH-. In this case, [OH-] = Kw / [H3O+] which would equal 2.94 x 10^-12 M.
What is the OH of a 4.0 x 10 4 M solution of CaOH2?
The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.
What does the slang word OMGD mean?
it means OH MY GOD!! O= oh M= my GD= god :)
How do you pronounce comment in french?
comb-oh or you could look at it as c-oh-m-oh
What is the pH of a 0.0110 M solution of Ba OH2?
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
Is eminem signing with WWE?
OH M G! See if he does!?
