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Oh, dude, a product of m and n is just the result of multiplying those two numbers together. It's like when you have m apples and n Oranges, and you're too lazy to count them individually, so you just smash them together and get the total. So yeah, the product of m and n is just m times n. Easy peasy, lemon squeezy.
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Product of 5m plus half of n?
5(m+/n
When a trinomial is factored as (x m)(x n) what is the product of m and n?
It is the constant term of the trinomial.
What is the product of m and n - 2?
Well, honey, the product of m and n minus 2 is simply mn - 2. It's as easy as pie, so don't overthink it. Just plug in your values for m and n, do the math, and voila! You've got your answer.
What are your two numbers if their sum is -5 and their product is 4?
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
What are th 4 fundamental laws in mathematics?
The Law of 4 Laws of addition and multiplication Commutative laws of addition and multiplication. Associative laws of addition and multiplication. Distributive law of multiplication over addition. Commutative law of addition: m + n = n + m . A sum isn't changed at rearrangement of its addends. Commutative law of multiplication: m · n = n · m . A product isn't changed at rearrangement of its factors. Associative law of addition: ( m + n ) + k = m + ( n + k ) = m + n + k . A sum doesn't depend on grouping of its addends. Associative law of multiplication: ( m · n ) · k = m · ( n · k ) = m · n · k . A product doesn't depend on grouping of its factors. Distributive law of multiplication over addition: ( m + n ) · k = m · k + n · k . This law expands the rules of operations with brackets (see the previous section).
