Q: What is a product of m and n?

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5(m+/n

It is the constant term of the trinomial.

Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.

The Law of 4 Laws of addition and multiplication Commutative laws of addition and multiplication. Associative laws of addition and multiplication. Distributive law of multiplication over addition. Commutative law of addition: m + n = n + m . A sum isn't changed at rearrangement of its addends. Commutative law of multiplication: m · n = n · m . A product isn't changed at rearrangement of its factors. Associative law of addition: ( m + n ) + k = m + ( n + k ) = m + n + k . A sum doesn't depend on grouping of its addends. Associative law of multiplication: ( m · n ) · k = m · ( n · k ) = m · n · k . A product doesn't depend on grouping of its factors. Distributive law of multiplication over addition: ( m + n ) · k = m · k + n · k . This law expands the rules of operations with brackets (see the previous section).

Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7

Related questions

Where m and n are statements m n is called the _____ of m and n.

38 or 46

If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2

The Cartesian product of two sets, A and B, where A has m distinct elements and B has n, is the set of m*n ordered pairs. The magnitude is, therefore m*n.

m+6n

5(m+/n

It is the constant term of the trinomial.

m+ (6n)

If two numbers have m and n significant digits, respectively, then then product can have at most m+n. However, the normally it is the minimum of m and n.

M+6n

it is not possible. Here is a simple explanation. Let m & n be whole numbers, so m² & n² are both perfect square numbers. Now multiply them together, and: m² * n² = (m*n)². Since m and n are both whole numbers, then m*n is a whole number, so (m*n)² is a perfect square.

The smallest positive number is 1. Since every positive number multiplied by 1 is the number itself as a product, then the product is neither less than 1 nor less that positive number. We can say the same for all the products of all other positive numbers. However, we can prove it: Let n, m > 0. Let suppose that nm < n or nm < m. So, nm < n divide by m to both sides; n < n/m is not true nm < m divide by n to both sides; m < m/n is not true Thus, the product of two positive numbers is always bigger than its factors.