5(m+/n
It is the constant term of the trinomial.
Well, honey, the product of m and n minus 2 is simply mn - 2. It's as easy as pie, so don't overthink it. Just plug in your values for m and n, do the math, and voila! You've got your answer.
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
The Law of 4 Laws of addition and multiplication Commutative laws of addition and multiplication. Associative laws of addition and multiplication. Distributive law of multiplication over addition. Commutative law of addition: m + n = n + m . A sum isn't changed at rearrangement of its addends. Commutative law of multiplication: m · n = n · m . A product isn't changed at rearrangement of its factors. Associative law of addition: ( m + n ) + k = m + ( n + k ) = m + n + k . A sum doesn't depend on grouping of its addends. Associative law of multiplication: ( m · n ) · k = m · ( n · k ) = m · n · k . A product doesn't depend on grouping of its factors. Distributive law of multiplication over addition: ( m + n ) · k = m · k + n · k . This law expands the rules of operations with brackets (see the previous section).
Where m and n are statements m n is called the _____ of m and n.
38 or 46
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
The Cartesian product of two sets, A and B, where A has m distinct elements and B has n, is the set of m*n ordered pairs. The magnitude is, therefore m*n.
m+6n
5(m+/n
It is the constant term of the trinomial.
m+ (6n)
If two numbers have m and n significant digits, respectively, then then product can have at most m+n. However, the normally it is the minimum of m and n.
Well, honey, the product of m and n minus 2 is simply mn - 2. It's as easy as pie, so don't overthink it. Just plug in your values for m and n, do the math, and voila! You've got your answer.
M+6n
it is not possible. Here is a simple explanation. Let m & n be whole numbers, so m² & n² are both perfect square numbers. Now multiply them together, and: m² * n² = (m*n)². Since m and n are both whole numbers, then m*n is a whole number, so (m*n)² is a perfect square.