The answer is 55. A mathematical formula for solving this problem would be n(n+1)/2, where n is the largest natural number that you wish to sum. In this case, n=10. Of course, if you are using a computer program like MS Excel, you can always use the SUM function.
Just add 1 + 2 + 3... etc.,
The first ten natural numbers are 1 through 10. To find their total, you can use the formula for the sum of the first n natural numbers, which is ( \frac{n(n + 1)}{2} ). For n = 10, the total is ( \frac{10(10 + 1)}{2} = \frac{10 \times 11}{2} = 55 ). Thus, the sum of the first ten numbers is 55.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
20100
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It is 10*(10+1)/2 = 55
The general equation to find the sum of the numbers 1 to n is: (n*(n+1))/2So, for n=10, you have:(10*(10+1))/2(10*11)/2110/255
Just add 1 + 2 + 3... etc.,
The first ten natural numbers are 1 through 10. To find their total, you can use the formula for the sum of the first n natural numbers, which is ( \frac{n(n + 1)}{2} ). For n = 10, the total is ( \frac{10(10 + 1)}{2} = \frac{10 \times 11}{2} = 55 ). Thus, the sum of the first ten numbers is 55.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
The sum of the first 10 counting numbers (1-10) is 51.
The composite numbers between 1 and 10 are 4, 6, 8, 9, 10. And their sum is 37.
20100
The two numbers 10 and -1: 10 × -1 = -10 10 + -1 = 10 - 1 = 9
Yes.
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11