Just add 1 + 2 + 3... etc.,
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
20100
1 1 1
11
It is 10*(10+1)/2 = 55
The general equation to find the sum of the numbers 1 to n is: (n*(n+1))/2So, for n=10, you have:(10*(10+1))/2(10*11)/2110/255
Just add 1 + 2 + 3... etc.,
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
The sum of the first 10 counting numbers (1-10) is 51.
The composite numbers between 1 and 10 are 4, 6, 8, 9, 10. And their sum is 37.
20100
Yes.
The two numbers 10 and -1: 10 × -1 = -10 10 + -1 = 10 - 1 = 9
1 1 1
11
Between -10 and 10 there are 9 natural numbers if exclusive of the -10 and 10, or 10 if inclusive. The natural numbers are the positive integers starting with 1, ie {1, 2, 3, ...}.