The sum of the first 10 natural numbers is 51, with an average of 5.1
The sum of the first 10 natural numbers is 51.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
The first ten positive numbers total 55.
2 + 3 + 5 = 10
The sum of the first 10 natural numbers is 51, with an average of 5.1
The sum of the first 10 natural numbers is 51.
It is 10*(10+1)/2 = 55
Yes
The sum of the first 10 even numbers is 110.
The sum of the first 10 odd whole numbers is 100.
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The numbers are 9, 10 and 11 with a sum of 30.
The sum of the first 10 counting numbers (1-10) is 51.
The sum of the first five whole numbers is 10.
The answer is 385
100