Approximately 50.265 square inches.
The surface area of this sphere is 2,827 square feet.
Surface area of a sphere in square units = 4*pi*radius^2
Surface area of a sphere = 4*pi*radius2 Surface area = 16*pi = 50.26548246 or 50 square inches.
Surface area of a sphere = 4*pi*radius2 The diameter is 17 feet so the radius is half of this i.e. 8.5 feet. 4*pi*8.52 = 907.9202769 square feet.
Approximately 50.265 square inches.
The surface area of this sphere is 2,827 square feet.
Approximately 50.265 square inches.
Surface area of a sphere in square units = 4*pi*radius^2
Surface area of a sphere = 4*pi*radius2 Surface area = 16*pi = 50.26548246 or 50 square inches.
The surface area is 1,020 square feet.
Surface area of a sphere = 4*pi*radius2 The diameter is 17 feet so the radius is half of this i.e. 8.5 feet. 4*pi*8.52 = 907.9202769 square feet.
A sphere with this volume has a diameter of 9.1416 cm, a surface area of 262.54 square cm and a circumference of 28.719 cm.
Oh, dude, you're hitting me with some math here. So, the formula for the surface area of a sphere is 4πr², where r is the radius. Since the diameter is 18 cm, the radius is half of that, which is 9 cm. Plug that into the formula, and you get a surface area of 1017π cm². But like, who's really gonna measure that in real life, am I right?
Calculate the radius (it is half the diameter).Use the formula for a sphere: area = 4 x pi x radius2.Since a hemisphere is half a sphere, divide this result by 2.Question:Do you mean the surface area to include the flat face of the hemisphere?If so then follow the above instructions and add pi*42 to your answer which will give you the complete surface area of the hemisphere.
The volume of a sphere whose diameter is 25 centimeters is 8,181 cubic centimeters
That's called a "great circle" of the sphere. -- It's any circle whose center is at the center of the sphere. -- Its diameter is equal to the diameter of the sphere. -- Its area is equal to 1/4 the surface area of the sphere. -- The shortest distance between any two points on the sphere is along the piece of the great circle on which they lie. (There's only one, unless the two points are the opposite ends of a diameter.)