It depends if it is affected by air resistance or not. If not then all objects close to the surface of the Earth have an acceleration of 9.81ms^-2 in free fall. If it is affected by air resistance you need all sorts of more information to answer that question, like the drag coefficient of the air.
0.7848 meter
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
The acceleration of gravity is 9.8 meters (32.2 ft) per second2.Neglecting air resistance . . .After 8 seconds, the speed is (9.8 x 8) = 78.4 meters per second. (rounded)After 8 seconds, the speed is (32.2 x 8) = 257.6 feet per second. (rounded)
none. when there is gravity T=2pi square root of L/g but in a freely falling elevator, there is no accelerate so it doesn't have period the answer is none
That depends on many different factors, the two most obvious ones being friction and gravity. If the object is completely frictionless, and falling at 9.8m/s2 (an approximation of the average acceleration from Earth's gravity), then it would gain 9.8m/s in speed with each second that passes. If on the other hand it was falling in a frictionless environment on Jupiter, it would gain approximately 24.79 m/s.
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
0.7848 meter
The acceleration of a freely falling object is approximately 9.81 m/s^2, directed downwards towards the center of the Earth. Therefore, the acceleration of the object 2 seconds after being released will still be 9.81 m/s^2, assuming no other forces are acting on it.
9.8 m/s2
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
A freely body is the body which is freely falling under the force of gravity i.e. an acceleration of 9.8 m/s2
Freely falling bodies undergo acceleration due to gravity, which is approximately 9.81 m/s^2 on Earth. This acceleration causes the speed of the falling object to increase as it falls towards the ground.
For freely falling objects, the equation of motion is modified to account only for the effects of gravity. The equation becomes: y = 0.5gt^2, where y is the height of the object at time "t" in seconds, and "g" is the acceleration due to gravity (approximately 9.8 m/s^2). Friction and other forces are typically ignored in these scenarios.
No effect whatsoever. Any two freely falling bodies fall with the same acceleration when dropped in the same place on the same planet. That includes any two objects falling on Earth. Someone is sure to jump in here and point out that objects with different mass don't fall with equal accelerations on Earth, and that's because of air resistance. They may even go on to provide answers to other questions that were not asked, such as a treatise on terminal velocity. All of that is true, even if confusing. This question stipulated that the bodies in question are "freely fallling". Bodies that are falling through air are not freely falling.
when the acceleration of the freely falling object is equal to the acceleration due to gravity then there occurs free fall.
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