To solve this, we take the change in speed and divide it by the change in time. 10 km/hr divided by 5/60 hr = 0.833 km/hr2
You can't figure "acceleration" from this information. Maybe you meant "Deceleration"? Ask again.
Magnitude of acceleration = (change in speed) / (time for the change) = 2/5 Acceleration = 0.4 meters per second2 north
Average acceleration = (change in speed) divided by (time interval)A = (40 - 25) / 15 = 15/15 = 1 meter/sec2
The answer depends on whether the rate of acceleration is uniform. There is no indication in the question that it is.
There is no acceleration if the car is travelling at a steady 54,000 miles per hour.
1.2 divided by 2 seconds equals .6m/s... i think. acceleration without speeding is when you're going in circles, but you feel like you're going faster.
You can't figure "acceleration" from this information. Maybe you meant "Deceleration"? Ask again.
Magnitude of acceleration = (change in speed) / (time for the change) = 2/5 Acceleration = 0.4 meters per second2 north
First, convert the speeds to SI units, that is, to meters/second. Then, simply subtract the difference in speed by the 2 seconds. The result will be in meters/sec2.
Average acceleration = (change in speed) divided by (time interval)A = (40 - 25) / 15 = 15/15 = 1 meter/sec2
if the bike goes from 0-5 in the same amount of time (2 seconds) then they are accelerating at the same rate.
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
The answer depends on whether the rate of acceleration is uniform. There is no indication in the question that it is.
If the car is going at a constant speed of 100 km/h, then its acceleration is zero. Acceleration measures the rate of change of velocity, and since the car's speed is not increasing or decreasing, there is no acceleration.
There is no acceleration if the car is travelling at a steady 54,000 miles per hour.
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
If the first car speeds up t seconds after being overtaken (t ≥ 0), and the acceleration is instantaneous, then the first car needs to travel at 96 + 41*t/(88 - t) mph Of course, acceleration will not be instantaneous, but then the formula WILL become a lot more complicated.