Wiki User
∙ 10y agoYou haven't mentioned the speed difference or speed gain in this question so it cannot be answered
Wiki User
∙ 10y agoacceleration = change in velocity divided by timeaccel = (9-3)/3 = 6/3 = 2 meters per second per second
If the ball started off stationary and the acceleration is the same for the 2 seconds, then the acceleration of the ball is:Speed / time = acceleration9 (m/s) / 2 (s) = 4.5 (m/s/s)Hope this helps.
9 Years = 284012568 Seconds
9 hours, 25 minutes, 59 seconds = 33,959 seconds.
60 seconds = 1 minute. 60 x 9 = 540 seconds.
To calculate acceleration between 6 and 9 seconds, you need to find the change in velocity during that time interval and then divide it by the time taken. The formula for acceleration is acceleration = (final velocity - initial velocity) / time. Plug in the velocities at 6 seconds and 9 seconds into the formula to get the acceleration.
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acceleration = change in velocity divided by timeaccel = (9-3)/3 = 6/3 = 2 meters per second per second
The answer will depend on its acceleration.
Acceleration can be calculated using the formula: acceleration = change in velocity / time taken. In this case, the change in velocity is 9 m/s and the time taken is 4 seconds. Therefore, the acceleration would be 9 m/s divided by 4 seconds, which equals 2.25 m/s^2.
Seconds from Disaster - 2004 Sinking the Coventry 6-9 was released on: USA: 24 December 2012
If the ball started off stationary and the acceleration is the same for the 2 seconds, then the acceleration of the ball is:Speed / time = acceleration9 (m/s) / 2 (s) = 4.5 (m/s/s)Hope this helps.
There are 32,400 seconds in 9 hours. This is calculated by multiplying 9 hours by 60 minutes (to convert hours to minutes), then by 60 seconds (to convert minutes to seconds).
A gain of 2 miles per second squared
9 Hours 32 Minutes and 31 Seconds - Not including any stops and time for acceleration
An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.
No.