His gravitational potential energy is greatest at the highest point in his vault. Viewing this problem ideally (where all outside factors are discarded), the pole vaulter's jump follows a parabolic path, and the vaulter will obviously be the furthest distance from the earth's surface when he reaches the highest point in the parabolic path and begins his descent. The gravitational potential energy of a single object with respect to the earth is given by U = mgh, where U is the energy given in joules, m is the mass of the object, g is the gravitational acceleration on earth (around 9.81 m/s2 toward the earth), and h is the positive distance from the earth's surface. In this problem, mass and acceleration are constant, since ideally, the only force acting on the vaulter is the force of gravity that will bring him back to the ground. Therefore, U is maximized at the highest point in the vault - the vertex of the parabola, halfway between the origin of his jump and the point where he hits the ground.
There is no way to tell unless a height is specified. Once you have that, you would divide the distance (height) by the time (2.5). Suppose 50 feet, and it took 5 seconds to reach that height. You would have 50/5 = 10 feet per second. given the acceleration of gravity is 9.81m/s2 and y=at2 then ymax = 9.81(2.5)2 OR 61.3125m At its highest point it has a velocity of zero. if 0=v0-at and a=9.81 and t=2.5 then v0 = 9.81(2.5) = 24.525 m/s
Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.
The next highest is 13. The highest hasn't been found yet.
The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!
The acceleration at the highest point when a ball is thrown straight up is equal to the acceleration due to gravity, pointing downwards (-9.8 m/s^2). At the highest point, the velocity of the ball is momentarily zero before it starts to fall back down.
The planets with the largest accelerations of gravity are those with the highest surface gravity. Mercury has the highest average surface gravity of all the planets, followed by Venus, Earth, and Mars. Jupiter, with its enormous mass, also has a high gravity acceleration at its cloud tops.
At the highest point of your jump, your acceleration is equal to -9.81 m/s^2, which is the acceleration due to gravity pulling you back towards the ground.
The acceleration of the ball at the highest point is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2. At the highest point of its trajectory, the ball momentarily stops moving upward before falling back down due to the force of gravity.
At the highest point, the velocity of the ball is zero because it momentarily stops before falling back down. The acceleration of the ball at the highest point is equal to acceleration due to gravity, which is directed downward toward the center of the Earth and is approximately 9.81 m/s^2.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
No, the acceleration at the highest point is never 0.
The acceleration is always directed downward due to gravity. At the highest point, the acceleration is still acting downward, but its magnitude is zero as the ball momentarily stops before descending back down.
At the highest point of its trajectory, the velocity of the ball will be zero since it comes to a stop before falling back down. The acceleration of the ball at this point will be equal to the acceleration due to gravity acting downwards, which is approximately 9.8 m/s^2.
As the coin is tossed upwards, its velocity decreases until it reaches its highest point where it momentarily stops before coming back down. The acceleration due to gravity is acting against the coin's motion, causing it to decelerate while ascending.
At the highest point, the speed of the ball is 0 m/s because it momentarily stops before falling back down. The acceleration at the highest point is equal to the acceleration due to gravity (approximately -9.8 m/s^2) acting in the downward direction.
Mercury has the highest surface gravity of the terrestrial planets. Its gravity is about 0.38 times that of Earth's gravity.