Q: What is the acceleration of an object effected by gravity thrown at a 45 degree angle above the horiziontal at its highest point?

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His gravitational potential energy is greatest at the highest point in his vault. Viewing this problem ideally (where all outside factors are discarded), the pole vaulter's jump follows a parabolic path, and the vaulter will obviously be the furthest distance from the earth's surface when he reaches the highest point in the parabolic path and begins his descent. The gravitational potential energy of a single object with respect to the earth is given by U = mgh, where U is the energy given in joules, m is the mass of the object, g is the gravitational acceleration on earth (around 9.81 m/s2 toward the earth), and h is the positive distance from the earth's surface. In this problem, mass and acceleration are constant, since ideally, the only force acting on the vaulter is the force of gravity that will bring him back to the ground. Therefore, U is maximized at the highest point in the vault - the vertex of the parabola, halfway between the origin of his jump and the point where he hits the ground.

There is no way to tell unless a height is specified. Once you have that, you would divide the distance (height) by the time (2.5). Suppose 50 feet, and it took 5 seconds to reach that height. You would have 50/5 = 10 feet per second. given the acceleration of gravity is 9.81m/s2 and y=at2 then ymax = 9.81(2.5)2 OR 61.3125m At its highest point it has a velocity of zero. if 0=v0-at and a=9.81 and t=2.5 then v0 = 9.81(2.5) = 24.525 m/s

Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.Find the highest number, eliminate it from the list, find the highest number of the remaining numbers.

The next highest is 13. The highest hasn't been found yet.

The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!The answer will depend on what the highest and lowest numbers are!

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The acceleration of the ball at the highest point is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2. At the highest point of its trajectory, the ball momentarily stops moving upward before falling back down due to the force of gravity.

At the highest point, the velocity of the ball is zero because it momentarily stops before falling back down. The acceleration of the ball at the highest point is equal to acceleration due to gravity, which is directed downward toward the center of the Earth and is approximately 9.81 m/s^2.

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As the coin is tossed upwards, its velocity decreases until it reaches its highest point where it momentarily stops before coming back down. The acceleration due to gravity is acting against the coin's motion, causing it to decelerate while ascending.

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