You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
It's an algbraic expession in the form of: 2n+4
I am assuming that 2n is an algebraic expression, and n is limited to positive integer values. The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
'n' can be any number, but when applied to (2n + 4), n = 2.5
2n plus 4 = 2n + 4
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
It's an algbraic expession in the form of: 2n+4
I am assuming that 2n is an algebraic expression, and n is limited to positive integer values. The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).
If you mean 2n+4, or 2n-4, that already is an algebraic expression. The idea might be to put it into words. 2n+4 is twice n, increased by 4. Notice you need a comma because if you write twice n increased by 4 this is 2(n+4)
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
t(n) = n2 - 2n + 4
'n' can be any number, but when applied to (2n + 4), n = 2.5
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1
10n = 7n + 4 + 2n so 10n = 9n + 4 Subtract 9n from both sides: n = 4
5n + 7 = 28 + 2n (-2n) 3n + 7 = 28 (-7) 3n = 21 therefore, n = 7
2n+4: 6,8,10......104........204