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I am assuming that 2n is an algebraic expression, and n is limited to positive integer values.
The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).
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What are the first four terms of a sequence for 2n plus 4 divided by 2?
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
How do you solve 17 plus 2n equals 21 plus 2n?
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
What is 2n plus 4?
It's an algbraic expession in the form of: 2n+4
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
What is the first 3 terms if the nth term is 2n?
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
Find the first 3 terms and 50th and 100th term for 2n plus 4?
2n+4: 6,8,10......104........204
How to write the phase for 2n plus 4?
2n plus 4 = 2n + 4
Slove multi-step equations 4n-2n 4?
If you mean: 4n-2n = 4 then 2n = 4 and n = 2
What are the first four terms of a sequence for 2n plus 4 divided by 2?
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
What is n in 2n-9 equals -4?
2n-9=-4
How do you solve 17 plus 2n equals 21 plus 2n?
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
What is 2n plus 4?
It's an algbraic expession in the form of: 2n+4
What is the algebric expression for 2n 4?
If you mean 2n+4, or 2n-4, that already is an algebraic expression. The idea might be to put it into words. 2n+4 is twice n, increased by 4. Notice you need a comma because if you write twice n increased by 4 this is 2(n+4)
Which is the complete factorization of 2n-6n-36?
First we must collect and simplify 'like terms' 2n-6n-36. 2n-6n = -4n Therefore, -4n-36 Take out the greatest common factor. -4 (n+9) Ans = -4 (n+9)
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
