3600 degrees
To find the sum of the interior angles of a polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 22-sided polygon, the calculation is ( (22 - 2) \times 180 = 20 \times 180 = 3600 ) degrees. Therefore, the sum of the interior angles in a 22-sided polygon is 3600 degrees.
The sum of the interior angles of a 22-sided polygon (icosikaitriangle) can be calculated using the formula ((n - 2) \times 180) degrees, where (n) is the number of sides. For a 22-sided figure, the sum of the interior angles is ((22 - 2) \times 180 = 20 \times 180 = 3600) degrees. Therefore, the sum of the interior angles of a 22-sided polygon is 3600 degrees.
To find the sum of the interior angles of a 24-sided polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 24-sided polygon, this would be ( (24 - 2) \times 180 = 22 \times 180 = 3960 ) degrees. Each interior angle can then be calculated by dividing this sum by the number of sides: ( 3960 / 24 = 165 ) degrees. Therefore, a 24-sided polygon has a total of 3960 degrees and each interior angle measures 165 degrees.
The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 22 sides, the sum of the interior angles is ( (22 - 2) \times 180^\circ = 20 \times 180^\circ = 3600^\circ ). Each interior angle of a regular 22-sided polygon would therefore be ( \frac{3600^\circ}{22} \approx 163.64^\circ ).
Basically when you have a 24 sided polygon you can split it up into 22 separate, non-overlapping triangles by drawing diagonals. Each triangle has 180 degrees, so the product, 22 times 180, gives you the sum of the interior angles of the 24 sided polygon.
It is: (22-2)*180 = 3600 degrees
163.64 degrees
Exterior angles: 360 degrees Interior angles: 3,600 degrees
44
3600
3600/22=163.63
To find the sum of the interior angles of a polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 22-sided polygon, the calculation is ( (22 - 2) \times 180 = 20 \times 180 = 3600 ) degrees. Therefore, the sum of the interior angles in a 22-sided polygon is 3600 degrees.
The sum of the interior angles of a 22-sided polygon (icosikaitriangle) can be calculated using the formula ((n - 2) \times 180) degrees, where (n) is the number of sides. For a 22-sided figure, the sum of the interior angles is ((22 - 2) \times 180 = 20 \times 180 = 3600) degrees. Therefore, the sum of the interior angles of a 22-sided polygon is 3600 degrees.
3600
The sum of the exterior angles of any polygon and the extension of its adjacent side is 360 degrees.If the 20 sided polygon is regular, then each angle is equal so that each one is 360/20 = 18 degrees.
(22-2)*180=3600
To find the sum of the interior angles of a 24-sided polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 24-sided polygon, this would be ( (24 - 2) \times 180 = 22 \times 180 = 3960 ) degrees. Each interior angle can then be calculated by dividing this sum by the number of sides: ( 3960 / 24 = 165 ) degrees. Therefore, a 24-sided polygon has a total of 3960 degrees and each interior angle measures 165 degrees.