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Can an obtuse isosceles triangle has two congruent sides and two obtuse angles?
No the answer is no people think about it a triangles sides all have to sum up to be 180 degrees.
Why do know that a right triangle has no obtuse interior angles?
All triangles have interior angles that add to 180 degrees. Let's call the 3 angles A,B, and C and angles A the 90 degree one. If 90+B+C=180. If angle B was the angle greater than 90 degrees (obtuse) then C would be 0 or negative degrees. Therefore, a right triangle can't have an obtuse interior angle. Sum of all angles in a triangle is 180o. In a right triangle one angle is 90o and other two angles sum up to 90o. A right triangle can't have an obtuse angle because obtuse angle is greater than 90o. So, sum of the two angles(right angle and obtuse angle) will be greater than 180o which is not possible.
What is the measure of an acute base angle of the trapezoid of an isosceles triangle vertex of 46 degrees?
For an isosceles triangle with vertex 46 degrees, the sum of the remaining two base angles is 180-46 = 134 degrees. Base angles are equal because it's isosceles, so each angle is half of their sum. 134/2 = 67 degrees. Thus, any isosceles trapezoid formed inside that isosceles triangle by drawing parallel lines to the triangle's base, will have base angle measures of 67 degrees, which are triangle's base angles.
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
What is he sum of the angles of an obtuse triangle?
The sum of the interior angles on an Obtuse Triangle is 1800 . This is true of ALL triangles.
