3000 miles = 190,080,000 inches = adjascent
1/2*3 inches = 1.5 inches = opposite (iscossolise tryangle = 2 right angle tryangle back to back)
tan = opposite/adjascent = 1.5/190,080,000 = 7.8914141414141414141414141414141e-9
tan-1 7.8914141414141414141414141414141e-9 = 4.5214472469288446723046398893908e-7 degrees*2 (back to iscosolies tryangle)= 9.0428944938576893446092797787816 e-7
so 0.000,000,9 degrees, assuming your measurements are accurate
The angular diameter (in radians) can be calculated using the formula: ( \theta = \frac{d}{D} ), where ( d ) is the linear diameter and ( D ) is the distance. In this case, ( d = 23 ) meters and ( D = 1500 ) meters (1.5 km). Thus, ( \theta = \frac{23}{1500} \approx 0.0153 ) radians. To convert this to degrees, multiply by ( \frac{180}{\pi} ), resulting in an angular diameter of approximately 0.88 degrees.
The question cannot be answered simply. A degree is a measure of angular displacement whereas an inch is a measure of linear displacement. If the angular displacement (in degrees) were measured at a distance r inches from some fixed point (the centre of rotation), then the linear displacement would be pi*r/180 inches.
6 inches across
What do you mean? 40 inches = 40 inches.
6 inches across
The angular diameter (in radians) can be calculated using the formula: ( \theta = \frac{d}{D} ), where ( d ) is the linear diameter and ( D ) is the distance. In this case, ( d = 23 ) meters and ( D = 1500 ) meters (1.5 km). Thus, ( \theta = \frac{23}{1500} \approx 0.0153 ) radians. To convert this to degrees, multiply by ( \frac{180}{\pi} ), resulting in an angular diameter of approximately 0.88 degrees.
The distance would be approximately 1.15 kilometers. This can be calculated using the formula: distance (in meters) = linear size (in meters) / tan(angular size in radians). The angular size of 100 seconds of arc is approximately 0.00048 radians (100/206265), and the tan of this angle is roughly 0.00048. Dividing 30 meters by 0.00048 gives us 62500 meters, which is 1.15 kilometers.
None. they are a measure of angular distance and not of linear distance.
18.4 inches
The question cannot be answered simply. A degree is a measure of angular displacement whereas an inch is a measure of linear displacement. If the angular displacement (in degrees) were measured at a distance r inches from some fixed point (the centre of rotation), then the linear displacement would be pi*r/180 inches.
linear velocity is a change of speed in a linear fashion. Angular speed is the rate of change of angle with respect to time. These two are convertible in a case of a circle motion. the lenght of an arc is l = RO. where O is the angle. hence v= l/t and therefore v=RA where A = O/t.
Angular acceleration and linear acceleration are related in a rotating object through the equation a r, where a is linear acceleration, r is the radius of the object, and is the angular acceleration. This equation shows that the linear acceleration of a point on a rotating object is directly proportional to the angular acceleration and the distance from the center of rotation.
6 inches across
The linear speed of a rotating object depends on its angular speed (how fast it rotates) and the distance from the axis of rotation (the radius). Linear speed is calculated as the product of the angular speed and the radius.
It is not possible to answer the question because of a mismatch in the units. A degree could be a measure of temperature and there is no relationship between temperature and length. A degree could be a measure of angular separation, but without any information on the radius (or diameter or circumference) of the circle or sphere, there is no way to relate that to a linear distance.
What do you mean? 40 inches = 40 inches.
angular momentum = linear momentum (of object) x perpendicular distance (from origin to the object) where x stands for cross product. angular momentum = mv x r (perpendicular dist.)