0
-x -2 = 1 - 2x
Add 'x' to both sides ( preserve equality ; balance)
-2 = 1 - x
Add '2' to both sides
0 = 3 -x
Add 'x' to both sides
x = 3 The Answer !!!!!
NB When said as 'adding/subtracting etc., to both sides', this is to preserve equality (=), so the eq'n remains 'balanced', just like a weigh scales.
e.g. with numbers.
5 = 3 + 2 , however, 5 - 2 = 3 ( same difference!!!!!).
What else can I help you with?
How can you rewrite equation x squared plus 12x plus 5 equals 3?
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
X2 plus 12x-64 equals 0?
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
What is the square of x2 plus 12x plus 20 equals 0?
168
X2 plus 12x minus 13 equals 0?
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
X2 plus 12x-6 equals 0?
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
How can you rewrite equation x squared plus 12x plus 5 equals 3?
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
X2 plus 12x-64 equals 0?
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
What is the square of x2 plus 12x plus 20 equals 0?
168
X2 plus 12x minus 13 equals 0?
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
X2 plus 12x-6 equals 0?
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
What is the constant term in X2 plus 12x minus 13 equals 0?
It is -13.
X2 plus 12x plus 36 equals 0?
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
X2 - 12x 36?
x2 - 12x + 36 = (x - 6)2
X2-12x plus 36 equals 11?
x=5/2*sqr(3)
What is the factorization of the trinomial -x2 plus 12x plus 28?
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
X2 - 12x plus 36?
x2-12x+36 = (x-6)2
X2 plus 12x equals 100?
There is no integer solution. Quadratic formula gives x = -17.66 or 5.66
