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Factorization of x2 plus 12x plus 27?
x2 + 12x + 27 = (x + 9)(x + 3)
Solve for x x2 plus 12x plus 36 equals 0?
x^2 + 12x + 36 = 0(x + 6)(x + 6) = 0(x + 6)^2 = 0√(x + 6)^2 = ± √0x + 6 = 0x + 6 - 6 = 0 - 6x = 6
In solving the quadratic equation x2 plus 12x - 5 equals 0 what value would complete the square?
x2 + 12x - 5 = 0x2 + 12x - 5 + 5 = 0 + 5x2 + 12x = 5x2 + 12x + (12/2)2 = 5 + (12/2)2x2 + 12x + (6)2 = 5 + 36(x + 6)2 = 41 (square root of both sides)x + 6 = ± √41x + 6 - 6 = -6 ± √41x = -6 ± √41x ≈ -6 + 6.4 = -0.4x ≈ -6 - 6.4 = -12.4
Express 72 as the difference of the square of 2 natural numbers?
72 = x2 + x2 x = 6 x2 = 36 36+36=72
What is X squared plus 12x plus 11 equals?
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
X2 - 12x plus 36?
x2-12x+36 = (x-6)2
X2 plus 12x plus 36 equals 0?
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
X2 plus 12x-6 equals 0?
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
Factor X2-12x plus 36 equals 0?
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
X2-12x plus 36 equals 11?
x=5/2*sqr(3)
What is the factorization of the trinomial -x2 plus 12x plus 28?
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
How can you rewrite equation x squared plus 12x plus 5 equals 3?
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
How do you Factor the following polynomial 6x2plus72xplus216?
6.(x2 + 12x + 36) = 6.(x + 6)(x + 6)
What are the Factors of X2 12x 36?
Assuming the missing signs are pluses, that factors to (x + 6)(x + 6)
What is the answer to completing the square to x2 plus 12x-11?
x2 + 12x - 11 = x2 + 12x + (12/2)2 - (12/2)2 - 11 = (x + 6)2 - 47
What number must you add to complete the square x2 12x -5?
I assume you mean,X2 + 12X - 5 = 0X2 + 12X = 5Now, halve the linear term (12), square it and add it to both sidesX2 + 12X + 36 = 5 + 36factor on the left, gather terms on the right(X + 6)2 = 41(X + 6)2 - 41 = 0==============vertex form.... (- 6, - 41)========================--------------vertexAnd that number added is 36
