256 = 28
256 (base 10) = 1104 (base 6)
256 base 10 = 100 base 16
4 * 4 * 4 * 4 (i.e. 44) = 256 (base 10). In base 2 (binary) this is:100000000.Which is 28.
31
128
pythagoreon thereom 34sq - 30sq = 256 sqrt = 16 base 16+16 = 32 half length of base = SQR(34^2 - 30^2) =SQR(1156-900) =SQR(256) =16 base length = 2x 16=32
The largest number with three digits in base two is 111, which equals seven. Other answer: largest 3 digit number = 999 base 2=binary 00000000000000000000000000=0 00000000000000000000000001=1 00000000000000000000000010=2 00000000000000000000000100=4 999/2=~500 log 500/log 2=8.9->9 ->9 zeroes after 1 2^9=512 1000000000=512 1100000000=512+256=768 1110000000=512+256+128=896 1111000000=512+256+128+64=960 1111100000=512+256+128+64+32=992 1111100111=512+256+128+64+32+4+2+1=999
256 = (16)2 256 = (2)8
The only prime factor of 256 is: 2
256 divided by 2 is 128.
2