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Pansy O'Hara
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∙ 8y ago3r - 3r = 0
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What is the answer to 2r plus r plus 4g plus r?
4r+4g
Simplify 2r plus 7r - 6t - r plus 7t?
2r + 7r - 6t - r + 7t = 8r + t
What is r in this equation and how do you do it minus 5 equals 7 plus 3r?
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
What is an equivalent expression to (3r) plus (ar) plus (4r)?
It is (7 + a)r.
What is the answer for this math algebra problem 3r-2 for r equals 65?
3r-2 for r=65
8 plus 2 8r-2r 4 3r plus 2 r 0 is the only solutionis this correct?
It is not correct to say that 8 plus 2 8r-2r 4 3r plus 2 r = 0
What is 3r-8 equals2-2r?
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
What is the sum of r - 10 and 100 - 3r?
r - 10 + 100 - 3r = -2r + 90
What is 3R?
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
R plus 3 plus 2r equals - 21?
r+3+2r=21 to solver this equation you have to first simplify then solve. you have to combine same variables. 3r+3=21 -3 -3 you subtract three to get r by itself (3r=18)/3 you divide by three to get r by itself Answer r=6
13r plus 10 equals 5r-46?
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
3r plus 6-6 equals 2r-12-6?
No, it's simply 3r, because multiplication (r multiplied by 3) comes first in the order of operations.
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
How can you find the first term of an arithmetic sequence if you know the third and fifth terms?
Suppose A is the first term and R is common difference. Then, if t(n) is the nth term, t(n) = A + n*R Then t(5) = A + 5R and t(3) = A + 3R so that t(5) - t(3) = 2R Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R) So t(1) = t(3) - 2R You were given t(3) and have calculated 2R above, so can work out t(1).
What is the solution to soukoban level 67?
Here's the solution to Soukoban Level 67 The letters U,D,R & L are your directions (up, down, right & left.) If there is a digit in front of the letter, move that many spaces in that direction (ex: 4U = four moves upward) Got it? Good! Here goes… 2U R U L 3D R U D L D L 2D R 4U 3D 2R 2D L 2D 2U 2R 2D L R 2U 2L D R 3U 2L 3U 2L 3U 2R 5D 2U 4R 2D L U R U 3L D L U 4R D 2R U L D R D L U 2L U 3L 2D L 2D R U 2R 2D 3R U 2D 2R D 2R 4U L U L U 2L 3D R 2D You've done a lot of prep work, but you still have a way to go before you can put those boxes into their permanent place… U L R D R D 2R 4U L U L U 4L D R U 3R D R D R 4D 2L U 2L 4U 4D 2R D 2R 4U L U L U 2L 2R D L 2R D R 4D 2L U 2L 4U R 3U R 2D L D L 4D 2R D 2R 4U L U L R D R 4D 2L U 2L 4U 2L 2U 3L 2D L 2D R U 2R 2D 3R D 3R D R 3U Hoorah! You've got your first box into place! But there's still much more to go… 2D 4L 2U R D L D 3R D R 2U D 4L 4U 2L 2U 2R 4D 4U 5L 2D L 2D R U 2R 2D 3R U R D L D 3R D R U 4L 5U 2R D L U L 3D 4U 5L 2D L 2D R U 2R 2D 3R U R D L D 3R You take it from here. Continue by filling the far two on the top row, then the far two on the bottom…you get the idea. Good Luck!
What is the answer to 2r plus r plus 4g plus r?
4r+4g
Simplify 2r plus 7r - 6t - r plus 7t?
2r + 7r - 6t - r + 7t = 8r + t
