4r+4g
2r + 7r - 6t - r + 7t = 8r + t
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
It is (7 + a)r.
Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3
It is not correct to say that 8 plus 2 8r-2r 4 3r plus 2 r = 0
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
r - 10 + 100 - 3r = -2r + 90
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
r+3+2r=21 to solver this equation you have to first simplify then solve. you have to combine same variables. 3r+3=21 -3 -3 you subtract three to get r by itself (3r=18)/3 you divide by three to get r by itself Answer r=6
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
No, it's simply 3r, because multiplication (r multiplied by 3) comes first in the order of operations.
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
Suppose A is the first term and R is common difference. Then, if t(n) is the nth term, t(n) = A + n*R Then t(5) = A + 5R and t(3) = A + 3R so that t(5) - t(3) = 2R Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R) So t(1) = t(3) - 2R You were given t(3) and have calculated 2R above, so can work out t(1).
Here's the solution to Soukoban Level 67 The letters U,D,R & L are your directions (up, down, right & left.) If there is a digit in front of the letter, move that many spaces in that direction (ex: 4U = four moves upward) Got it? Good! Here goes… 2U R U L 3D R U D L D L 2D R 4U 3D 2R 2D L 2D 2U 2R 2D L R 2U 2L D R 3U 2L 3U 2L 3U 2R 5D 2U 4R 2D L U R U 3L D L U 4R D 2R U L D R D L U 2L U 3L 2D L 2D R U 2R 2D 3R U 2D 2R D 2R 4U L U L U 2L 3D R 2D You've done a lot of prep work, but you still have a way to go before you can put those boxes into their permanent place… U L R D R D 2R 4U L U L U 4L D R U 3R D R D R 4D 2L U 2L 4U 4D 2R D 2R 4U L U L U 2L 2R D L 2R D R 4D 2L U 2L 4U R 3U R 2D L D L 4D 2R D 2R 4U L U L R D R 4D 2L U 2L 4U 2L 2U 3L 2D L 2D R U 2R 2D 3R D 3R D R 3U Hoorah! You've got your first box into place! But there's still much more to go… 2D 4L 2U R D L D 3R D R 2U D 4L 4U 2L 2U 2R 4D 4U 5L 2D L 2D R U 2R 2D 3R U R D L D 3R D R U 4L 5U 2R D L U L 3D 4U 5L 2D L 2D R U 2R 2D 3R U R D L D 3R You take it from here. Continue by filling the far two on the top row, then the far two on the bottom…you get the idea. Good Luck!
4r+4g
2r + 7r - 6t - r + 7t = 8r + t