If 4x - 2x + 4 = 10, the solution is 2x + 4 = 10 and x = 3.
2x - 10 =30 2x -10 = 30 +10 +10 2x = 40 /2 /2 x = 20
2x-2 = 10 2x= 10+2 2x=12 x= 12/2 x=6
2x - 8 = 10 2x = 10 + 8 2x = 18 x = 18 / 2 x = 9
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
If 4x - 2x + 4 = 10, the solution is 2x + 4 = 10 and x = 3.
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3
4 - 2x = 10 -2x = 10-4 -2x = 6 -x = 3 x = -3
2x - 10 =30 2x -10 = 30 +10 +10 2x = 40 /2 /2 x = 20
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
2x-2 = 10 2x= 10+2 2x=12 x= 12/2 x=6
2x + 4 = 10 2x = 10 - 4 = 6 2x = 6 x = 6/2 = 3
2x - 8 = 10 2x = 10 + 8 2x = 18 x = 18 / 2 x = 9
3x+9=2x+10 3x+9-2x=10 9+x=10 x=1
3-2x-2 = 10 -2x = 10+2-3 -2x = 9 x = -4.5
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
2x+10=12 2x=2 x=1