The answer is every point on the line in the Cartesian plane which is defined by the equation.
You have one linear equation in two unknown variables. In order to solve for two variables you need two independent linear equations.
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3x + 2y = 7
3x-2y-7=0
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
(-1, 5)
3x + 2y = 7
3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0
3x-2y-7=0
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
3x+2y-7=0 2y=-3x+7 y=1/2(-3x+7) or -3/2 x +7/2
(-1, 5)
(-1, 5)
Standard form is: y = Mx + b so you must solve for y 3x = 2y + 7 3x - 7 = 2y 2y = 3x - 7 y = ( 3 / 2 )x - ( 7 / 2 )
(3, -4)
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7