y=6
-7x+9y = 54 9y = 7x+54 y = 7/9x+6 which is now in slope-intercept form
9y-11=7 +11 +11 9y=18 y=2
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
9
y=6
-7x+9y = 54 9y = 7x+54 y = 7/9x+6 which is now in slope-intercept form
To find the value of ( y ) when ( x = 11 ), we can substitute ( x ) with 11 in the equation ( 7x - 9y = 23 ) and solve for ( y ): [ 7(11) - 9y = 23 ] [ 77 - 9y = 23 ] [ -9y = 23 - 77 ] [ -9y = -54 ] [ y = \frac{-54}{-9} ] [ y = 6 ] So, when ( x = 11 ), ( y = 6 ).
Y-8x plus 9y equals 10y-8x.
9y-11=7 +11 +11 9y=18 y=2
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
-9y + 8 = -91-9y = -91 -8-9y = -99y = -99-----9y = 11-99/-9 = 11 because -9X11 = -99
9
9y = 12.6 y = 1.4
-9
9y
92y = 36 y = 36/92 = 9/23 Then: 9y = 81/23