If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
y^2 + 7y + 12 = (y+4)(y+3)
y2+7y=18 y2+7y-18=0 (y+9)(y-2)=0 y=-9 & y=2
7y + 18 = 39 Therefore, 7y = 39 - 18 = 21 y = 21/7 y = 3
x = 7y x/7 = y
y=-9 7y-2=14y+61 7y-2-7y=14y+61-7y -2=7y+61 -2-61=7y+61-61 -63=7y -63/7=7y/7 -9=y
Yx7y = 7y2 (squared )
If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
y^2 + 7y + 12 = (y+4)(y+3)
x + 7y = 7 ⇒ 7y = -x + 7 ⇒ y = -x/7 + 1 ⇒ y intercept is 1.
y2+7y=18 y2+7y-18=0 (y+9)(y-2)=0 y=-9 & y=2
7y + 18 = 39 Therefore, 7y = 39 - 18 = 21 y = 21/7 y = 3
x = 7y x/7 = y
simplify the expression 16+7y-8 rewrite as 7(y-8)7•y= 7y 7•8= 56 7y-56 = -49y answer= 16+ (-49y)
5x = 7y , we divide both side by 'y' 5x/y = 7y/y (y will now be deducted) 5x/y = 7 x/y = 7/5 Therefore, x:y = 7:5
-2
3y=7y+24.4 First, try to get all the y-terms on the same side of the equation. Easily done here by subtracting 7y from both sides 3y-7y=7y-7y+24.4 -4y=24.4 Now divide by -4 -4y/-4=24.4/-4 y=-6.1