Yx7y = 7y2 (squared )
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-6y+3 = -7y+8 -6y+7y = 8-3 y = 5
35
T = 3x + 7y; x = 4; y = 6T = 3x + 7y (substitute 4 for x, and 6 for y)T = 3(4) + 7(6) = 12 + 42 = 54
5x - 7y = 5 (subtract both sides by 5x) -7y = -5x + 5 (divide both sides by -7) y = (5x - 5)/7 If you want to solve for y = 0, then x = 1.
15x+7y = 4 5x+7y = 2 Subtract the bottom equation from the top equation to eliminate y which will leave you with: 10x = 2 Divide both sides by 10 to find the value of x: x = 2/10 = 1/5 in its lowest terms. Substitute the value of x into the original equations to find the value of y: Therefore: x = 1/5 and y = 1/7