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So the base is 25 meters squared, that leaves 60 for the triangles.

the equation for triangles is base x height x 1/2

5 times 6 is 30 divide by 2 is 15 times 4 is 60.

the answer is 6

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Q: What is the answer for The surface area of a square pyramid is 85 square meters. The base length is 5 meters. What is the slant height?

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The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)

To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.The area of the base of the pyramid will be 6.32The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32SA ~= 103.84 m2

A cylinder that has a diameter of 10 meters and a height of 3 meters has a surface area of 251.33m2

A cylinder with a height of 10 meters and diameter of 4 meters has a surface area of 150.8m2

1/3*8*4.6*height = 88 height = (3*88)/(8*4.6) = 7.174 meters rounded to 3 decimal places

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It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.

Calculate the area of the 5 individual triangles that make the pyramid and the area of the pentagonal base and add these six areas together. Atriangle = 1/3 Base x Height Apentagon = (Perimeter x Apothem)/2 Apothem = side length/(2Tan(∏/Number of sides))

To find the height of the pyramid, use the formula for the volume of a pyramid: V = (1/3) * base area * height. Plug in the values given: 2226450 = (1/3) * 215^2 * height. Solve for height: height = 2226450 / ((1/3) * 215^2). Calculate the result to find the height of the pyramid.

The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)

slant height of the pyramid Louvre in Paris=28 meters

Nissan Primera: length = 4.567 meters; height = 1.482 meters

180 meters to 300 meters height length 14ft

To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.The area of the base of the pyramid will be 6.32The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32SA ~= 103.84 m2

A cylinder with a radius of 6 meters and a height of 10.5 meters has a surface area of 622.04m2

A cylinder with a height of 20 meters and a diameter of 10 meters has a surface area of 785.4m2

A cylinder that has a diameter of 10 meters and a height of 3 meters has a surface area of 251.33m2

A cylinder with a height of 10 meters and diameter of 4 meters has a surface area of 150.8m2