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If a square pyramid has a base of 6.3 meters and a height of 4 meters what is the surface area?
Wiki User
∙ 14y ago
To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.
So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.
The area of the base of the pyramid will be 6.32
The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32
SA ~= 103.84 m2
Wiki User
∙ 14y ago
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What is the surface area of a cylinder with a radius of 5 meters and a height of 4 meters?
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So the base is 25 meters squared, that leaves 60 for the triangles. the equation for triangles is base x height x 1/2 5 times 6 is 30 divide by 2 is 15 times 4 is 60. the answer is 6
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The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
What is the surface area of the right square pyramid in square meters?
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What is the volume of a square pyramid with base edges of 20 meters and a height of 30 meters?
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The pyramid shown has a square base that is 1818 inches on each side. The slant height is 1616 inches. What is the surface area of the pyramid?
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What is the surface area of a cylinder with a radius of 5 meters and a height of 4 meters?
The circumference of that cylinder would be 31.4156 meters, and with a height of 4 meters, the outside surface of the sides would be 125.66 square meters. Does a cylinder have both an inside and outside surface? There is no thickness at all to the sides. Maybe it needs to be doubled, to be 251.32 square meters so we get both inside and outside surface, but I think not. A cylindrical *prism* would have a top and bottom, each having a surface of 78.54 square meters, for a total of 282.74 square meters.
What is the surface area of a square pyramid when 4 is the side length and 13 as the slant height?
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What is the answer for The surface area of a square pyramid is 85 square meters. The base length is 5 meters. What is the slant height?
So the base is 25 meters squared, that leaves 60 for the triangles. the equation for triangles is base x height x 1/2 5 times 6 is 30 divide by 2 is 15 times 4 is 60. the answer is 6
What is the lateral area of a pyramid whose base is a square with sides measuring 16 meters and a slant height of 17 meters?
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What is the lateral surface area of this square pyramid that has a base length of 4 centimeters and a slant height of 9 centimeters?
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The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
What is the lateral area and surface area of a regular square pyramid?
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