A system of equations?
2X - Y = 3
X + Y = 6
I will try substitution. Express one variable in terms of the other ( use X + Y = 6 )
X + Y = 6
Y = - X + 6
insert into other equation
2X - ( - X + 6) = 3
2X + X - 6 = 3
3X = 9
X = 3
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put that back into one of the equations
(3) + Y = 6
Y = 3
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check both equations
2(3) - (3) = 3
6 - 3 = 3
3 = 3
first equation checks
(3) + (3) = 6
6 = 6
Both equations check
X = 3
Y = 3
are both true solutions for this system of equations
15xy-2xy-7x+x=13xy-6x
Y=15/(2c+2x)
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
2xy=2*30*2=120
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
It's an hyperbola equation.
15xy-2xy-7x+x=13xy-6x
Y=15/(2c+2x)
Because 2x+y is addition not multiplication
2xy + 6xy = 8xy
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
2xy=2*30*2=120
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
That equals 2xy + 3y which factors to y(2x + 3)
L = 3x + 2y
What is : 5xy- x2t + 2xy + 3x2t
2xy substitute 3 for y and 5 for x 2(5)(3) = 30