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X(3-2xy) , x=2 , y=1
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Solve simultaneously y equals 2-x and x2 plus 2xy equals 3?
if y = 2- x then x^2 + 2x(2 - x) = 3 ie x^2 + 4 x -2x^2 = 3 ie 4x - 3 = x^2 x^2 - 4x +3 = 0 = (x - 1)(x - 3) so x = 1 or 3 Check: y= 2 - 1 =1; x^2 = 1, 2xy = 2 x 1 x 1 = 2, 1 +2 = 3. y = 2 - 3 = -1; x^2 = 9, 2xy = 2 x 3 x -1 = -6, 9 + -6 = 3. QED.
What is 2xy times x?
To find the product of 2xy and x, you multiply the coefficients (2 and 1) to get 2, then multiply the variables x and x to get x^2, and finally multiply the variables y and 1 to get y. Therefore, the result of 2xy times x is 2x^2y.
What times -5 equals 3?
To find the value of x in the equation -5x = 3, you need to isolate x. Divide both sides by -5 to solve for x: x = 3 / -5 = -0.6. Therefore, -5 times -0.6 equals 3.
What times 3 equals 5?
1.66666666666667 x 3 = 5
If 5 x-3 equals 2-8 x then x equals?
5x-3=2-8x 5x-3+3=2-8x+3 5x=5-8x 5x+8x=5-8x+8x 13x=5 x=5/13
How do you evaluate 2xy times 9 if x equals 3 and y equals 2?
2xy*9 if x=3 and y = 2 2(3)(2)*9 12*9 108 You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.
(x2 + 2y) (x3 - 2xy + y3)?
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
Evaluate 2xy when x equals 30 and y equals 2?
2xy=2*30*2=120
Simplify 15xy-2xy-7x plus x equals?
15xy-2xy-7x+x=13xy-6x
How do you solve 2xy plus 6 equals 4xyz for y?
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
Solve simultaneously y equals 2-x and x2 plus 2xy equals 3?
if y = 2- x then x^2 + 2x(2 - x) = 3 ie x^2 + 4 x -2x^2 = 3 ie 4x - 3 = x^2 x^2 - 4x +3 = 0 = (x - 1)(x - 3) so x = 1 or 3 Check: y= 2 - 1 =1; x^2 = 1, 2xy = 2 x 1 x 1 = 2, 1 +2 = 3. y = 2 - 3 = -1; x^2 = 9, 2xy = 2 x 3 x -1 = -6, 9 + -6 = 3. QED.
When x-y equals 7 and xy equals 8 find the value of x square plus y square?
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
If Y' equals 2xy plus x to power 3 what is y equal to?
Assuming y' is dy/dx, y = x^4/4 + yx^2
2xy + 2xy squared?
(x + 4y)(x - 6y)
What is x-8 equals -3?
-5
What is the answer to x plus 5 equals 3?
x + 5 = 3 x = -2
What is 3 times x equals 5?
If: 3x = 5 then x = 5/3
