2-3
If you mean y = 2x+1 then the slope is 2 and the y intercept is 1
2
y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1) xy - y = 2x + 1xy - 2x = y + 1x(y - 2) = y + 1so x = (y + 1)/(y - 2) assuming y�2.So the inverse function is f-1(x) = (x + 1)/(x - 2)
Assuming you want to find the point at which those two lines intercept: We are told: y - 2x = -3 ∴ y = 2x - 3 We are also told: 4x - y = -1 ∴ 4x - (2x - 3) = -1 ∴ 2x - 3 = -1 ∴ 2x = 2 ∴ x = 1 Now we know the value of x, and can plug it back into either of the original equations to find y: y = 2x - 3 ∴ y = 2 - 3 ∴ y = -1 So the lines defined by these equations intercept at the point (1, -1).
y = 2x + 1 IS a linear equation!
2x - y -(-1) = 2x - y + 1
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-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)
Y = 2x + 1
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
-1
y = 2x
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
If you mean y = 2x+1 then the slope is 2 and the y intercept is 1
Which means 0 = -1!
Slope-Intercept Form: y = -2x +1
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