0
-6x = 6y + 6
-6x = 3y - 12
Subtracting the second from the first gives:
-6x - -6x = 6y - 3y + 6 - -12
→ 0 = 3y + 18
→ 3y = -18
→ y = -6
Substituting in the first:
-6x = 6y + 6
→ -6x = 6(-6) + 6
→ -6x = -36 + 6
→ -6x = -30
→ x = 5
Thus x = 5, y = -3 solve the simultaneous equations.
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Continue Learning about Math & Arithmetic
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