0
What do you mean?
As this is a calculus question, I presume that you are asking for a derivative or integral
The derivative of any function of the form
ƒ(x) = a * x ^ n
is
ƒ'(x) = a * n * x ^ (n-1)
The integral of any function of the form
∫ a*x ^ n
is
a / (n+1) * x ^ (n+1) + C
Your function that you gave is 1 / x^(2)
which is equal to:
x^(-2)
Thus the derivative is:
-2 * x^(-3)
And the integral is:
-x^(-1) + C
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