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What do you mean?

As this is a calculus question, I presume that you are asking for a derivative or integral

The derivative of any function of the form

ƒ(x) = a * x ^ n

is

ƒ'(x) = a * n * x ^ (n-1)

The integral of any function of the form

∫ a*x ^ n

is

a / (n+1) * x ^ (n+1) + C

Your function that you gave is 1 / x^(2)

which is equal to:

x^(-2)

Thus the derivative is:

-2 * x^(-3)

And the integral is:

-x^(-1) + C

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