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(a+b)/2 - 10 a+b divided by 2 and then minus 10
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When dividing a smaller number into a larger number, subtract the exponents. 8 x 10^5 divided by 4 x 10^2 = 2 x 10^3
I added A & B to your question for clarity. If a number (A) is divided by number (B) with no remainder, then A isdivisible by B. Also, it can be stated that B is a factor of A.
|x-3|/2=10 |x-3|=20 |a|=b means a=b or a=-b Then : x-3=20 or x-3=-20 So: x=23 or x=-17
(a+b)/2 - 10 a+b divided by 2 and then minus 10
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b/2=2ab/+b means112.5
yes, 10 teams are divided in 2 group A&B
When dividing a smaller number into a larger number, subtract the exponents. 8 x 10^5 divided by 4 x 10^2 = 2 x 10^3
I added A & B to your question for clarity. If a number (A) is divided by number (B) with no remainder, then A isdivisible by B. Also, it can be stated that B is a factor of A.
It is a linear equation in one variable, b. 4b + 8/-2 = 10 4b - 4 = 10 4b = 14 b = 14/4 = 3.5
first you forget the 2 is there. then you go : 1/10 x 1/10 x 1/10 x 1/10 x 1/10 x 1/10 = b now make b a 2. 2 x 10 -6 is 0.000002.
(100 - 100 / 100 - 100) = 2 => 102 - 102 / 10(10 - 10) =2 => (10 + 10) (10 - 10) / 10(10 - 10) = 2 [a2 - b2 = (a + b) (a - b)] Cancelling ( 10 - 10 ) {numerator} from ( 10 - 10 ) {denominator} => ( 10 + 10 ) / 10 = 2 => 20 / 10 = 2 => 2 = 2 [Hence, Proved]
This cannot be solved. If you have 2 unknowns (a,b) then you must have 2 equations.
|x-3|/2=10 |x-3|=20 |a|=b means a=b or a=-b Then : x-3=20 or x-3=-20 So: x=23 or x=-17