The perimeter of a triangle is the sum of the lengths of the three sides.If the three expressions in the question are in fact the lengths of thethree sides, then the perimeter is their sum.(7x + 9w) + (2x + 8y) + (2y + 5w) = 9x + 10y + 14w
2y+8y = 10y
- 7x + (9x - 3) = - 7x + 9x - 3 = 2x - 3
10y + 8y = 18y = 15 y = 15/18 y = 5/6 = 0.833333.....
9x+6 = 7x+18 9x-7x = 18-6 2x = 12 x = 6
The perimeter of a triangle is the sum of the lengths of the three sides.If the three expressions in the question are in fact the lengths of thethree sides, then the perimeter is their sum.(7x + 9w) + (2x + 8y) + (2y + 5w) = 9x + 10y + 14w
7 pigs - 8 chickens + 9 pigs = 16 pigs - 8 chickens7 exes - 8 wyes + 9 exes = 16 exes - 8 wyes7x - 8y + 9x = 16x - 8y
If you mean (9x-8y)(9x+8y) then it is 81x^2 minus 64y^2
2y+8y = 10y
- 7x + (9x - 3) = - 7x + 9x - 3 = 2x - 3
7x - 9x = -2x
10y + 8y = 18y = 15 y = 15/18 y = 5/6 = 0.833333.....
9x plus 8y
LCM(10y2 , 8y) = 40y2
it would simply still be 7x+8y You must have "like terms" to add variables meaning they both must be x or y . so your answer would still be 7x+8y
17
9x-4 = 7x+8 9x-7x = 8+4 2x = 12 x = 6