(8x-8y)/(8x+8y) = (x-y)/(x+y)Cancel down by 8; you have simplified the equation.
-8x-8y=-64 -8y=8x-64 y=-x+8
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
2x + 8y --- has a GCF of 2= 2(x + 4y)
The GCF is 4.
8y^3 - 3y^2 = y^2(8y - 3)
The oroduct of 'y' and '8' is 8y
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
4y + 8y = 12y 4y - 8y = -4y 4y x 8y = 32y2 4y/8y = 1/2
8y-79 = -71
6y-8y = -2
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
Yes, the equation 3x = 8y is a linear equation. A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a single variable raised to the first power. In this case, both 3x and 8y fit this definition, making it a linear equation.
Not sure which you mean, take your pick: (8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or 8y3+27=(2y+3)(4y2-6y+9)
-2
(8x-8y)/(8x+8y) = (x-y)/(x+y)Cancel down by 8; you have simplified the equation.
2y+8y = 10y