ax + b = 15 or ax + b = -15
It is a straight line with gradient -A/B and intercept C/B.
y = (c - Ax) / (B)
a function
Ax + By = CSubtract 'Ax' from each side:By = -Ax + CDivide each side by 'B' :y = -(A/B)x + C/BThe slope of the line is -(A/B) .The y-intercept is (C/B) .
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
ax - b = c ax = b + c x = (b + c)/a
ax + b = 15 or ax + b = -15
It is a straight line with gradient -A/B and intercept C/B.
x = b/(a + c)
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
y = (c - Ax) / (B)
If x is a null matrix then Ax = Bx for any matrices A and B including when A not equal to B. So the proposition in the question is false and therefore cannot be proven.
a function
Ax + By = CSubtract 'Ax' from each side:By = -Ax + CDivide each side by 'B' :y = -(A/B)x + C/BThe slope of the line is -(A/B) .The y-intercept is (C/B) .
ax - b = c Add 'b' to both sides ax = c + b Divide both sides by 'a' x = (c + b) / a The answer!!!!!
A linear equation.