It is an algebraic expression in the form of: 10q-45
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-10
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
30q3 + 14q2 - 4q = 0 can be factored as q(30q2 + 14q - 4) = 0 The bracketed term can be factored (30q2 + 14q - 4) = (10q - 2)(3q + 2) The equation can now be written : q(10q - 2)(3q + 2) = 0 The equation = 0 when either q = 0 or one of the bracketed terms = 0 When 10q - 2 = 0 then q = 2/10 = 1/5 : and when 3q + 2 = 0 then q = -2/3.
To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.
70-q-q-2q = 70-4q = 80-4q = 10q=-10/4 = -5/2 = -2.5