10y plus 40 equals 50y.
-6 - 10y = -10 Add 6 to both sides: -10y = -4 Divide both sides by -4: y = -4/-10 = 4/10 = 0.4 Check by putting the value back into the equation: -6 - (10 x 0.4) = -6 -4 = -10
The points are: x = 0 and y = -1/10.
10y = 5 y = 5/10 Therefore, y = 0.5
10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5
10y = 9y + 4, so y = 4
8x - 10y = 27x - 5y = 13First, we need to eliminate one of the variables. For this, we would like to have them with the same coefficient but different sign. We can do this if we multiply by -2 the second equation.8x - 10y = 2-2(7x - 5y) = -2(13)8x - 10y = 2-14x +10y = -26Now, we can add both equations, and solve for x.(8x - 10y) + (-14x + 10y) = (2) + (-26)(8x - 14x) +(-10y + 10y) = (2 - 26)-6x = - 24-6x/-6 = - 24/-6x = 4Substitute 4 for x in the first equation:8x - 10y = 28(4) - 10y = 232 - 10y = 232 - 32 - 10y = 2 - 32-10y = -30-10y/-10 = -30/-10y = 3Thus, the solution of the system is (4, 3).Check:
10y plus 40 equals 50y.
4x-10y=11 4x=11+10y 10y+11=4x 10y=4x-11 y=(4/10)x-(11/10) y=(2/5)x-(11/10)
-6 - 10y = -10 Add 6 to both sides: -10y = -4 Divide both sides by -4: y = -4/-10 = 4/10 = 0.4 Check by putting the value back into the equation: -6 - (10 x 0.4) = -6 -4 = -10
The points are: x = 0 and y = -1/10.
10y = 5 y = 5/10 Therefore, y = 0.5
You're there. 4x = 10y - 8.[so subtract 10y from both sides, 4x - 10y = -8]multiply b.s. by -1 , gives -4x +10y = 8
10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5
x = 6y = 89x + 10y = 9(6) + 10(8) = 54 + 80 = 134
what is the solution of x-5y=10 and 2x-10y=20
24 divided by 6 equals 4.