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What is 52 equal 4 plus (n-1) x 3?
52 = 4 + (n-1)3 → 3(n-1) = 48 → n - 1 = 16 → n = 17
Find 3 consecutive numbers where the product of the two smaller numbers is 52 less than the square of the larger number?
Denote the lowest of the three consecutive numbers as n. Then the other numbers are n +1 and n +2. From the problem statement, n(n + 1) = (n + 2)2 -52, or: n2 + n = n2 + 4n + 4 - 52, or 3n = 48, or n = 16. Check: 16 X 17 = 272; 18 X 18 = 324; 324 - 272 = 52.
How would you do n plus 15 equals 52 what would be n?
n+15 = 52 n = 52-15 n = 37
16 52 as simplest form?
4/13 is the answer to 16/52 because 4 times 4= 16 and 4 times 13 = 52
Find 3 consecutive even numbers where the product of the smaller two number is 52 less than the square of the largest number?
6, 8, 10. 102 is 100. Subtract 52 from that, and you get 48, which is 6.8 Method: call the smaller of the unknown even numbers n. Then, from the problem statement, n(n+2) + 52 = (n + 4)2. Multiplying out yields n2 + 2n + 52 = n2 + 8n + 16. Collecting like terms from both sides yields 6n = 36 or n = 6.
