The idea here is to combine terms that have the same variable (or, in more complicated cases, the same combination of variables). For example, 3a + 2a is the same as 5a.
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∙ 2017-03-01 15:00:57Maseeh Good
7a plus 7b
Anonymous
E
Anonymous
8
Anonymous
I don’t know
5a + 11
-8a + 3a = (-8 + 3)a = (5)a = 5a
9a +8 -2a -3 -5a = 2a +5
It is: 7a+1 when simplified
No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
5a + 11
(6a3 - 19a2 + 15a)/(2a - 3) = a(6a2 - 19a + 15)/(2a - 3) = a(2a - 3)(3a -5)/(2a -3) = a(3a - 5)
depends what 'a' =
2a + 4b - 52a + 4b - 52a + 4b - 52a + 4b - 5
(3a+4)/12 - (5/3) = (2a-1)/2Multiply each side by 12:(3a+4) - (20) = 6 (2a-1)Eliminate the parentheses:3a + 4 - 20 = 12a -63a -16 = 12a -6Add 6 to each side:3a -10 = 12aSubtract 3a from each side:-10 = 9aDivide each side by 9:-10/9 = a
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
2a-5=-3a5a-5=05a=5a=0
The problem 3a-1 and 2a-5 is greater by 7. This is a math problem.
= 3 X 2 = 6 = a X a = a2 (a square) = 6a2 + 5 Answer