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What is the Greatest Common Factor of 32x4 and 4x2?
The GCF is 4x2.
What is 32x4?
A calculator might have been a bit quicker. But the answer is 128
What is 128 divide by 4?
32
What is four bushels?
Well, one bushel is 32 quarts, so 32x4=128. So, four bushels is technically 128 quarts. Hope it helped! :))
What is 32 multiplied by 4?
32 multiplied by 4 is 128. An easy way to find this in your head is to multiply each part separately. So- first multiply 30 x 4, then 2 x 4, and add them together to get your answer. 30x4 =120 2x4 =8 120+8=128 32x4=128
What are the coefficients of the binomial x plus 2 to the power of 6?
(x+2)6 (x2 + 4x + 4)(x+2)4 (x2 + 4x + 4)(x2 + 4x + 4)(x+2)2 (x2 + 4x + 4)(x2 + 4x + 4)(x2 + 4x + 4) (x4 + 4x3 + 4x2 + 4x3 + 16x2 + 16x + 4x2 + 16x + 16)(x2 + 4x + 4) (x4 + 8x3 + 24x2 + 32x + 16)(x2 + 4x + 4) (x6 + 4x5 + 4x4 + 8x5 + 32x4 + 32x3 + 24x4 + 96x3 + 96x2 + 32x3 + 128x2 +128x + 16x2 + 64x + 64) (x6 + 12x5 + 60x4 + 160x3 + 240x2 + 192x +64) the coefficeints are 1, 12, 60, 160, 240, and 192
6 girls are travelling on the bus each of them have 2 baskets in each basket there are 4 cats each cat has 4 kittens two girls are getting off the bus how many legs are there on the bus?
For each girl: 4 kittens per cat, 4 cats per basket, 2 baskets, 2x4=8 8x4=32 32x4=128 8x3=32 1x2=2 128+32+2=162x4=648 legs.The above assumes two girls have left the bus. Alternately:Assumptions:> Assumes the girls are not yet off the bus as stated "6 girls are travelling on the bus... two girls are _getting off_ the bus" and as a result are still on the bus at the time of the leg count> Assumes that the kittens are with the cats in the basket and not at home> Assumes there is a driver and they have legs, but are not included as they are not referenced in the statement> Assumes no other passengers, animals, milliepedes or other creatures on the bus> Assumes no disembodied legs aboard> Assumes no tables with legs> Assumes legs on bus seats as information not provided> Assumes "standard" number of legs per animal / person> Assumes there is no ticket inspector> Assumes the baskets don't have legs> Assumes health and safety investigator/Animal Safety officer not on board to monitor 20 cats per basket. These are some big baskets.6 girls with 2 legs each= 6 * 2 legs= 12 legs6 girls have 2 baskets of 4 cats with 4 legs each= 6 * 2 * 4 * 4 legs= 192 legs6 girls have 2 baskets of 4 cats with 4 kittens with 4 legs= 6 * 2 * 4 * 4 * 4 legs= 768 legsTotal Legs= 12 + 192 + 768= 972 legs
