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How do you solve 3n-6 equals 9?
Let's give it a go:3n - 6 = 9Add 6 to each side of the equation:3n = 15Divide each side by 3:n = 5
3n plus 6 equals n plus 20?
3n + 6 = n + 202n = 14n = 7
How do you do 3n plus 6 equals -9?
3n + 6 = -9 Subtract 6 from both sides: 3n = -15 Divide both sides by 3: n = -5 Therefore n = -5
When the reciproral of three times a number is substracted from the reciprocal number the result is one sixth find the number?
Let n be the number, then: 1/n - 1/3n = 1/6 Solve the subtraction on the left: 1/n - 1/3n = 3/3n - 1/3n = 2/3n But we know this is 1/6, thus: 2/3n = 1/6 ⇒ 3n = 12 ⇒ n = 4 Thus the number is 4.
What is the value of n in the equation 3n-6 equals 15?
73n-6+6=15+63n=213n/3=21/3n=7
The product of a number and 3 is 6?
6=3n or 3n=6
How do you get this 3n plus 2 plus (3n plus 3 - 3n plus 1)?
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
What is 3n plus 6 equals 18?
3n+6=18 n+2=6 n=4
How do you solve 3n-6 equals 9?
Let's give it a go:3n - 6 = 9Add 6 to each side of the equation:3n = 15Divide each side by 3:n = 5
3n plus 6 equals n plus 20?
3n + 6 = n + 202n = 14n = 7
How do you do 3n plus 6 equals -9?
3n + 6 = -9 Subtract 6 from both sides: 3n = -15 Divide both sides by 3: n = -5 Therefore n = -5
What is 15 9 plus 3n?
Assume the expression is: 15 = 9 + 3n Subtract both sides by 9 to get: 15 - 9 = 9 - 9 + 3n 6 = 3n Finally, divide both sides by 3 to get: 6/3 = 3n/3 n = 2
When the reciproral of three times a number is substracted from the reciprocal number the result is one sixth find the number?
Let n be the number, then: 1/n - 1/3n = 1/6 Solve the subtraction on the left: 1/n - 1/3n = 3/3n - 1/3n = 2/3n But we know this is 1/6, thus: 2/3n = 1/6 ⇒ 3n = 12 ⇒ n = 4 Thus the number is 4.
What is the value of n in the equation 3n-6 equals 15?
73n-6+6=15+63n=213n/3=21/3n=7
What is 3n equals 18?
How do you find the answer to this equation: 3n equals 18
When combining like terms do you add the exponents together?
Yes when multiplying. No when adding. 3n^3 + 3n^3 = 6n^3 3n^3 x 3n^3 = 9n^6
The sum of three times a number and 6 is 39 Find the number?
3n + 6 = 39Therefore 3n = 39 - 6 = 33n = 33 / 3Therefore, n = 11
