(4, -1)
x = 4 and y = -1 (4. -1)
If: 2x+5y = 2 and -3x-y = -3Then it works out that: x = 1 and y = 0
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
y=-3/2x + 1/2
(4, -1)
y=(-1) x=(2)
x = 4 and y = -1 (4. -1)
Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
6x2+6xy-3x
Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
X = -2(13 + y) / 3x = 5y / 4 - 1
If: 2x+5y = 2 and -3x-y = -3Then it works out that: x = 1 and y = 0
3x-5y=7 5x-2y=-1
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
2x^2y^2(3x^2y^3 - 2xy + 1)
If the question is to solve the system of the equations of two variables, then:Let y = f(x) = 2x - 5, andlet y = g(x) = -3x - 1So we have:y = 2x - 5y = -3x - 12x - 5 = -3x - 12x + 3x -5 + 5 = -3x + 3x - 1 + 55x = 4x = 4/5y = 2x - 5y = 2(4/5) - 5y = 8/5 - 5y = 8/5 - 5 x 5/5y = 8/5 - 25/5y = (8 - 25)/5y = -17/5Thus, the solution of the system is x = 4/5 and y = -17/5.