Assuming y=2x+5 and x=2y-15
y=2x+5 (1)
x=2y-15 (2)
Substitute y=2x+5 into (2):
x=2(2x+5)-15
x=4x+10-15
0=3x+10-15
0=3x-5
5=3x
5/3=x (x=5/3)
Substitute x=5/3 into y=2x+5:
y=2(5/3)+5
y=10/3+5
y=25/3
x=5/3, y=25/3
Yes it is!
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
2X - 5Y = 10 subtract 2X from each side - 5Y = - 2X + 10 divide each side by - 5 Y = 2/5X - 2 slope(m) = 2/5
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
This is Simultaneous equ'ns. 3x + 5y = -1 2x -5y = 16 Add the two eq'ns. This will eliminate 'y' Hence 5x = 15 x = 3 When x = 3 , substitute into either eq'n to yimnd 'y'. Hence 3)3) + 5y = -1 9 + 5y = -1 5y = -10 y = -10/5 = -2 So the solution in ( x,y) form is ( 3, -2).
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
If you mean 2x+5y = -10 then the y intercept is -2
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
(10, 2)
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.