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if a,b are any two numbers then a+b=b+a
a = k/b when a is inversely proportional to b, where k is a constant.
In one day A does 10% of the work and B does 12½%, so after A's 6 days he has done 60%, leaving 40% for B who will need three-and-a-fifth days to complete the work.
(a + b) = a^2 + 2ab + b^2 (a - b)^2 = a^2 - 2ab + b^2 or you can work like this: [a + (-b)]^2 = a^2 + 2a(-b) + (-b)^2 (a - b)^2 = a^2 - 2ab + b^2
0.5 * (a + b) * h