4X^2 + 11X + 6 = 0
looks like larger than 1 by the discriminant and needing the quadratic equation to solve.
-b +/- sqrt(b^2-4ac)/2a
a = 4
b = 11
c = 6
-11 +/- sqrt[11^2 - 4(4)(6)]/2(4)
-11 +/- sqrt(25)/8
[-11 +/- (5)]/8
X = -3/4
x = -2
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It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
23 + 15x - 4x = 1215x - 4x = 12 -2311x = -11x= -1
Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
11x+9=7x+21 11x-7x=4 4x+9=21 21-9=12 4x=12 12 divided by 4= 3 x=3
If: y = 4x^2 -12x -3 and y = x^2 +11x +5 Then: 4x^2 -12x -3 = x^2 +11x +5 Transposing terms: 3x^2 -23x -8 = 0 Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8 Therefore the x coordinates are: -1/3 and 8