If: y = 4x^2 -12x -3 and y = x^2 +11x +5
Then: 4x^2 -12x -3 = x^2 +11x +5
Transposing terms: 3x^2 -23x -8 = 0
Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8
Therefore the x coordinates are: -1/3 and 8
They intersect at the point of: (-3/2, 11/4)
They touch each other at (0, 100) on the x and y axis.
If: y = 1 -x^2 -8x -16 and y = x^2 +3x -10 Then: x^2 +3x -10 = -x^2 -8x -15 Or: 2x^2 +11x +5 = 0 Factorizing the above: (2x+1)(x+5) = 0 meaning x = -1/2 or x = -5 When x = -1/2 then by substitution y = -45/4 When x = -5 then by substitution y = 0 Therefore it follows coordinates of intersection are at: (-1/2, -45/4) and (-5, 0)
If: y = 5x^2 -2x +1 and y = 6 -3x -x^2Then: 5x^2 -2x +1 = 6 -3x -x^2Transposing terms: 6x^2 +x -5 = 0Factorizing: (6x -5)(x +1) = 0 => x = -1 or x = 5/6Through substitution points of intersect are at: (-1, 8) and (5/6, 101/36)
If you mean the graph, then the lowest coordinates would be (0,0). Also known as the origin.
They intersect at the point of: (-3/2, 11/4)
Because when collated together the discriminant of b2-4ac = -32 i.e. 144-(4*2*22) = -32 In order for the parabolas to make contact with each other the discriminant must equal zero or be above zero.
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
If you mean the coordinates of the line x-y = 2 that intersects the curve of x2-4y2 = 5 Then the coordinates work out as: (3, 1) and (7/3, 1/3)
They touch each other at (0, 100) on the x and y axis.
If: y = 1 -x^2 -8x -16 and y = x^2 +3x -10 Then: x^2 +3x -10 = -x^2 -8x -15 Or: 2x^2 +11x +5 = 0 Factorizing the above: (2x+1)(x+5) = 0 meaning x = -1/2 or x = -5 When x = -1/2 then by substitution y = -45/4 When x = -5 then by substitution y = 0 Therefore it follows coordinates of intersection are at: (-1/2, -45/4) and (-5, 0)
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then the length of the line works out as: 65/18 or 3.6111 ... recurring decimal 1
If: y = 5x^2 -2x +1 and y = 6 -3x -x^2Then: 5x^2 -2x +1 = 6 -3x -x^2Transposing terms: 6x^2 +x -5 = 0Factorizing: (6x -5)(x +1) = 0 => x = -1 or x = 5/6Through substitution points of intersect are at: (-1, 8) and (5/6, 101/36)
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
If you mean the graph, then the lowest coordinates would be (0,0). Also known as the origin.
There is no connection between the given curves because when they are combined into a single quadratic equation the discriminant of the equation is less than zero which means they share no valid roots.
type you answer here!