log(x) + 4 - log(6) = 1
so
log(x) + 4 + log(1/6) = 1
Take exponents to the base 10 and remember that 10log(x) = x:
x * 104 * 1/6 = 10
x = 6/1000 or 0.006
Using the properties of logarithms, specifically the quotient rule, we can simplify the expression log₆ 60 - log₆ 30 to log₆ (60/30). This simplifies to log₆ 2, since 60 divided by 30 equals 2. Therefore, log₆ 60 - log₆ 30 = log₆ 2.
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
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Original Statement:x - 1 + 2 + log(x) = 3Simplify:x + 1 + log(x) = 3Subtract 1:x + log(x) = 2Lambert W-Function:x = (W(100*ln(10))/(ln(10)) = 1.7555794993... (rounded up).This considered log(x) to be base 10 log (x).
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Using the properties of logarithms, specifically the quotient rule, we can simplify the expression log₆ 60 - log₆ 30 to log₆ (60/30). This simplifies to log₆ 2, since 60 divided by 30 equals 2. Therefore, log₆ 60 - log₆ 30 = log₆ 2.
log1 + log2 + log3 = log(1*2*3) = log6
log644 - log64 = log6(44/4) = log611
That can't really be simplified. I can though be rewritten: Log 6 = x is another way of saying: 10x = 6
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
No. Insert the word "minus" in place of the word "plus", and you'll have a true statement.
log(-3,2.3914850069628266…i) = 1.26ie. (-3)1÷1.26=2.3914850069628266…i
log(6) or log10(6) = 0.778 (3sf). Therefore 100.778 = 6 (if you did not understand logarithms).
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Original Statement:x - 1 + 2 + log(x) = 3Simplify:x + 1 + log(x) = 3Subtract 1:x + log(x) = 2Lambert W-Function:x = (W(100*ln(10))/(ln(10)) = 1.7555794993... (rounded up).This considered log(x) to be base 10 log (x).
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
True