answersLogoWhite

0

What else can I help you with?

Related Questions

-9(a plus b)?

The simplified expression is -9a -9b.


What is 9b-13b equals 40?

9b-13b= -4b -4b = 40 Divide both sides by -4 b = -10


What is the answer to this equation 5a plus 3b plus 9b-10a?

It is not an equation but an algebraic expression that can be simplified to: 12b-5a


What is b - 9b simplified?

What I would do is change the problem up. Instead of b-9b I would make it -(9b-b). It is still the same problem; you will multiply the number inside the parenthesis be -1. So start with 9b-b. That would equal 8b. So it would change from -(9b-b) to -(8b) so you multiply 8b by negative 1 (-1) to get the answer -8b. -8b is your answer. So b - 9b = -8b


What is 3a plus 5b minus 6a minus 9b?

3a + 5b - 6a - 9b = -3a - 4b


What is the simplified form of (3b 7)2?

If you mean: (3b+7)^2 then it is 9b^2+42b+49


Factor the expression given below 144A2 - 81B2?

(12a+9b)(12a-9b)


What is 7b b b simplified?

If you mean: 7b+b+b then it is 9b simplified


What is the algebra expression 7a-9b?

-2ab


15b plus 2 - 13 equals 13b plus 6 - 4b?

15b+2-13 = 13b+6-4b 15b-11 = 9b+6 15b-9b = 6+11 6b = 17 b =17/6 or 2 and 5/6


How many terms in 6a plus 9b plus 15?

There are 3 terms in the given expression of 6a+9b+15


Factor by groupin 4b2 plus 9b-28?

4b² + 9b - 28 = 4b² + 16b - 7b - 28= 4b (b + 4) - 7 (b + 4)= (4b - 7) (b + 4),which is the desired answer.This method can be called 'grouping' or 'splitting the middle term'.* * *The trick, as you can see, is in the judicious splitting of 9b into 16b - 7b.After all, there are infinite ways in which 9b may be split.(Examples: 9b = 14b - 5b; or 9b = 20b - 11b; neither of which gives any help at all. You can try, and see!)The real question is, which way of splitting 9b will help us factorise the original expression, and how can we find it? Trial and error will find it, of course; but, as in the present example, trial and error can sometimes become rather tedious.* * *Here is a very helpful rule, which works whenever the trinomial given is factorisable:(Since the three co-efficients in the present example are 4, 9, and -28, in that order, I will express the rule in terms of those three co-efficients.)Find two numbers whose sum is 9 and whose product is equal to4 × (-28) = -112.(Note that the sum must equal the co-efficient of the middle term, namely, 9.)These two numbers will be found to be 16 and -7. Thus, we will choose to represent 9b as 16b - 7b, and factorisation should proceed smoothly.