original problem: c2-10c+24=0 reverse foil: (c-6)(c-4)=0 so... c-6=0 OR c-4=0 +6 +6 +4 +4 c=6 OR c=4
l a2 b2 is c2!!Its completely norma
C2 + 10C + 25 The expression is a perfect square, so both factors are the same. (C + 5) and (C + 5)
52+32 = c2 34 = c2 c = the square root of 34
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
original problem: c2-10c+24=0 reverse foil: (c-6)(c-4)=0 so... c-6=0 OR c-4=0 +6 +6 +4 +4 c=6 OR c=4
a2
l a2 b2 is c2!!Its completely norma
C2 + 10C + 25 The expression is a perfect square, so both factors are the same. (C + 5) and (C + 5)
Pythagorean Theorem
a right triangle
52+32 = c2 34 = c2 c = the square root of 34
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
12c
You just typed it.
* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73
c= -2 2/7 OR -2.285714